Write the equation of the tangent to the curve `y=x^2-x+2` at the point where it crosses the y-axis.

The equation to the tangent to the curve y = be ^(-x/a) at the point where it crosses the y-axis is

The equation of the tangent to the curve y= be^(-(x)/(a)) at the point where it crosses the y-axis is-

Write the equation of the tangent to the curve y=[x] at the point (-2,2).

Equation of the tangent to the curve y=2x^3_6x^2-9 at the point where the curve crosses the y -axis is

Write the equation of the tangent to file curve y=|x| at the point (-2, 2).

The equation of the tangent to the curve y=be^(-x/a) at the point where it crosses the y-axis is a)(x)/(a)-(y)/(b)=1( b) ax+by=1 c)ax -by=1( d) (x)/(a)+(y)/(b)=1

The equation of tangent to the curve y=b^(-x//a) at the point where it crosses Y-axis is

Find the slope of the tangents to the curve y=x^2(x+3) at the points where it crosses the x-axis.