Displacement-time equation of a particle executing SHM is x=4sin`omega`t+3tsin(omegat+pi//3)`
Here, x is in cm and t ini sec. The amplitude of oscillation of the particle is approximately.

Displacement-time equation of a particle executing SHM is x=4sin( omega t) + 3sin(omegat+pi//3) Here, x is in cm and t ini sec. The amplitude of oscillation of the particle is approximately.

Displacement time equation of a particle executing SHM is, x = 10 sin ((pi)/(3)t+(pi)/(6))cm . The distance covered by particle in 3s is

Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2"to"x=+A/2

The equation of an SHM is x=8 sin omega t + 15 cos omega t , where x is displacement and t is time . The amplitude will be

Displacement-time equation of a particle execution SHM is x=A sin( omegat+pi/6) Time taken by the particle to go directly from x = -A/2 to x = + A/2 is

Displacement-time equation of a particle execution SHM is x=A sin( omegat+pi/6) Time taken by the particle to go directly from x = -A/2 to x = + A/2 is

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?