`DeltaG` for the reaction `:`
`(4)/(3) Al+O_(2)rarr (2)/(3)Al_(2)O_(3)`
is `-772 kJ mol^(-1)` of `O_(2)`.
Calculate the minimum `EMF` in volts required to carry out an electrolysis of `Al_(2)O_(3)`

Delta G for the reaction (4)/(3) Al + O_(2) rarr (2)/(3) Al_(2)O_(3) is -772kJ mol^(-1) of O_(2) . Calculate the minimum EMF in volts required to carry out an electrolysis of Al_(2)O_(3)

On the basis of information available from the reaction (4)/(3)Al+O_(2) rarr (2)/(3)Al_(2)O_(3),DeltaG = -827kJ mol^(-1) of O_(2) , the minimum emf required to carry out of the electrolysis of Al_(2)O_(3) is (F=96,500 C mol^(-1))

On the basis of information available from the reaction (4)/(3)Al+O_(2) rarr (2)/(3)Al_(2)O_(3),DeltaG = -827kJ mol^(-1) , the minimum emf required of O_(2) to carry out of the electrolysis of Al_(2)O_(3) is (F=96,500 C mol^(-1))

On the bassis of the information available from the reaction 4/3 Al + O_2 rarr 2/3 Al_2 O_3 . Delta G =- 82 7 k J "mol"^(-1) of O_2 the minimum emf required to carry out an electorlysis of Al_2 O_3 is (F= 96500 C "mol"^(-1))

27 gm of Al will react completely with: 4Al + 3O_(2) rarr 2Al_(2)O_(3)

Balance the follwowing equations. 1) Al(OH)_(3)rarr Al_(2)O_(3)+H_(2)O