In Figure, line `l` is the bisector of angle `A\ a n d\ B` is any point on `ldotB P\ a n d\ B Q` are perpendiculars from `B` to the arms of `Adot` Show that: ` A P B\ ~= A Q B` BP=BQ or B is equidistant from the arms of `/_A`

line l is the bisector of an angle /_A\ a n d/_B is any point on l. BP and BQ are perpendiculars from B to the arms of /_A . Show that: (i) DeltaA P B~=DeltaA Q B (ii) BP = BQ or B is equidistant from the arms of /_A

In Figure, line l is the bisector of angle A and B is any point on l . B P and B Q are perpendiculars from B to the arms of Adot Show that : A P B~=A Q B B P=B Q or B is equidistant from the arms of /_A . Figure

In Figure, line l is the bisector of angle A and B is any point on l . B P and B Q are perpendiculars from B to the arms of Adot Show that : A P B~=A Q B B P=B Q or B is equidistant from the arms of /_A . Figure

Line l is the bisector of an angle angleA and B is any point on li. BP and BQ are perpendicular forms B to the arms of angleA . Show that: triangleAPB ~= triangleAQB (ii) BP = BQ or B is equidisitant from the arms of angleA .

In the given figure, line l is the bisector of an angle angleA and B is any point on l. If BP and BQ are perpendiculars from B to the arms of angleA , show that (i) DeltaAPB~=DeltaAQB (ii) BP = BQ, i.e., B is equidistant from the arms of angleA .

Line l is the bisector of an angle angleA and B is any point on l. BP and BQ are perpendiculars from B to the arms of angleA show that: triangleAPBequivtriangleAQB

Line l is the bisector of an angleA and B is any point on I. BP and BQ are perpendiculars from B to the arms of angleA (see figure). Show that: DeltaAPB~=DeltaAQB

Line l is the bisector of an angle angleA and B is any point on l. BP and BQ are perpendiculars from B to the arms of angleA show that: BP=BQ or B is equidistant from the arms of angleA

Line l is the bisector of an angleA and B is any point on I. BP and BQ are perpendiculars from B to the arms of angleA (see figure). Show that: BP=BQ or B is equidistant from the arms of angleA .

Line l is the bisector of an angle angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A (see Fig. 7.20). Show that: (i) triangle APB cong triangle AQB (ii) BP = BQ or B is equidistant from the arms of angle A .