What is the value of k in the following nuclear reaction ?
`U^235 + n to Ba^141 + Kr^92 + 3x^k` ( n is the symbol of neutron )

Complete the following nuclear equations : ._92U^235 + ._0n^1 to ._56Ba^141 + ._36Kr^92 + ___ ._0n^1

Complete the following nuclear reaction. _(92)^(236)U rarr_(56)^(141)Ba +___+ Energy .

Complete the following nuclear fission reactions : (a) ""_(92)^(235) U +_(0)^(1) n to_56 Ba + ^92 Kr + 3 _(0)^(1) n + ...... (b) ""_(92)^(235) U +_(0)^(1) n to^148 La +_(35)^(85) Br + ...... _(0)^(1) n + en ergy

Calculate the energy released in the following nuclear reaction and hence calculate the energy released when 235 gram of uranium-235 undergoes fission. U_(92)^(235) + n_(0)^(1) to Kr_(36)^(92) + Ba_(56)^(141) + 3n_(0)^(1) Rest masses of U^(235), Ba^(141) ,Kr^(92) and neutron are 235.04390 amu, 140.91390 amu, 91.89730 amu and 1.00867 amu respectively. Avogadro number = 6.023 xx 10^(23) .

What is the number of proton and neutron in ""_(92)X^(235) ?

Rewrite and complete the following nuclear reaction by filling in the atomic number of Ba and mass number of Kr : ""_(92)^(235)U+""_(0)^(1)nto""_(...)^(144)Ba+""_(36)^(...)Kr+3""_(0)^(1)n+"Energy"