The distance travelled by a motor car in t second after the brakes are applied is a feet, where s = 22t `-12t^(2)`.

The distance travelled by a motor car in t seconds after the brakes are applied is s feet where s = 22t -12t^(2) . The distance travelled by the car before it stop is

The distance travelled by a motor car in t second after the brakes are applied is s feet, where s = 22t -12t^(2) . The distance travelled by the car before it stops, is

The distance travelled by a motor car in t seconds after the brakes are applied is s feet where s=22t-12t^(2) . The distance travelled by the car before it stops, is

The distance x metres travelled by a vehicle in time t seconds after the breakes are applied is given by x=20 t-(5)/(3) t^(2) . Determine (i) the speed of the vehicle (in km /hr) at the instant the brakes are applied and (ii) the distance the car travelled before it stops.

The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

The distance s feet travelled by a particle in time t seconds is given by s = t^(3) - 6 t^(2) - 4t - 8 . Its acceleration vanishes at time t =

If the distance s travelled by a particle in time t is s=a sin t +b cos 2t , then the acceleration at t=0 is

A car accelerates from rest with 2 m // s^(2) on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is 100 m in 20 seconds. Then, the maximum velocity attained by the car is