If `p = 216^(1//3) + 243^(-2//5) + 256^(-1//4)`, then which of the following is an integer?

4xx(256)^((-1)/4) div (243)^(1/5)=

1/(216)^(-2/3) + 1/(256)^(-3/4) + 1/(243)^(-1/5) is equal to:

If (1-p) (1+3x + 9x^(2) + 27x^(3) + 81 x^(4) + 243 x^(5)) = (1-p^(6)) (p != 1) , then the value of (p)/(x) will be -

Write G.P. If a = 256, r = (-1)/2 .

( 1+3+5+7+9+11 )^ (3/2) = (a)36 (b) 216 (c)256 (d) none of these

( 1+3+5+7+9+11 )^ (3/2) = (a)36 (b) 216 (c)256 (d) none of these

In a G,P, T_(2) + T_(5) = 216 and T_(4) : T_(6) = 1:4 and all terms are integers, then find its first term :