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(AB)^(T) is :...

`(AB)^(T)` is :

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If A and B are square matrices of the order and if A=A^(T),B=B^(T) , then (ABA)^(T) is equal to a) BAB b) ABA c)ABAB d) AB^(T)

If A is matrix of order 3 such that |A|=5 and B= adj A, then the value of ||A^(-1)|(AB)^(T)| is equal to

If A and B are matrices of the same order, then AB^(T)-B^(T)A is a a ( a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix

If A and B are two matrices for which conformability for multiplication is assured, then prove (AB)^(T) = B^(T)A^(T)

If A={:[(2,1),(3,4)]:} and B={:[(1,-2),(-1,1)]:} verify that, (AB)^(T)=B^(T)A^(T) where A^(T) is the transpose of A.

Verify that (AB)^(T) = B^(T) A^(T) if A= [(2,3,-1),(4,1,5)] and B= [(1,-2),(3,-3),(2,6)]

Verify that (AB)^(T) = B^(T) A^(T) if A = ({:( 2 , 3 , -1) , (4 , 1 , 5):}) and B = ({:( 1 , 2) , ( 3 , -3) , (2 , 6)):}

Verify that (AB)^(T) = B^(T)A^(T) where A=|[1,-2,2],[3,1,-1]| and B=|[2,4],[1,2],[3,-2]| .

If the orders of matrices A^(T),BandC^(T)" are "3xx4,2xx3and1xx2 respectively, then the order of the matrix (AB^(T))C is

If A={:[(1,2,5),(-1,3,-4)]:} and B={:[(3,-2,1),(0,-1,4),(5,2,-1)]:}, show that, (AB)^(T)=B^(T)A^(T) where A^(T) is the transpose of A.