The width of an interference fringe is 1.5 mm . What would be the width of the fringe if the separation between the slits is made twice the original value?

In YDSE, when separation between two slits is increased, fringe width

What happens to fringe width, whne the separation between the slits as well as distance of the screen from the slit are halved?

To increase the angular width of interference fringes

In a biprism experiment, the width of fringe is 0.12 mm when the eyepiece is at a distance of 100 cm from the slit. What would be the width of the fringe if the eyepiece is moved towards the slit by 25 cm ?

Fringe width of an interference fringe is y for the two given waves. If the frequency of the source becomes double then the fringe width have been

In an interference experiment with a biprism, the distance of the slits from the screenn is increased by 25% annd the separation between the slits is halved. If X represents the original fringe width, the new fringe width will be

In Young's experiments the separation of slits is made 2 times. The fringe width will become

In a YDSE experiment, the distance between the slits & the screen is 100 cm . For a certain distance between the slits, an interference pattern is observed on the screen with the fringe width 0.25 mm . When the distance between the slits is increased by Deltad=1.2 mm, the fringe width decreased to n=2//3 of the original value. In the final position, a thin glass plate of refractive index 1.5 is kept in front of one of the slits & the shift of central maximum is observed to be 20 fringe width. Find the thickness of the plate & wavelength of the incident light.