The enthalpy of formation of ammonia is `-46.0 kJ mol^(-1)`. The enthalpy for the reaction `2N_(2)(g)+6H_(2)(g)to4NH_(3)(g)`

The enthalpy of formation of ammonia is -46.0 kJ mol^(-1) .The enthalpy for reaction 2N_2(g)+6H_2(g) rarr 4 NH_3(g) is equal to

The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g) is :

The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g) is :

The enthalpy of formation of ammonia is x KJ mol^(-1) . The enthalpy of the reaction 2N_2(g)+6H_2(g) rarr 4NH_3(g)

The enthalpy of formation of ammonia is -46.0kJ mol^-1. The enthalpy change for the reaction, 2NH_3(g)rarrN_2(g)+3H_2(g) is:

The enthalpy of formation of ammonia is - 46.2 mol^(-1) . The enthalpy change for the reaction 2NH_(3) rarr N_(2) + 3 H_(2) is

Enthalpy of formation of ammonia is - '46.0 kJ mol^(-1)'. The enthalpy change for the reaction: '2 NH_3(g) rarr N_2(g)+3 H_2(g)'