Potential energy `v//s` position curve for one dimensional conservative field is shown. Force at A and B is respectively.

The potential energy U of a body of unit mass moving in one dimensional conservative force field is given by U=x^2-4x+3 . All units are is SI. For this situation mark out the correct statement (s).

Potential energy of a body in position A is-40J. Work done by conservative force in moving the body from A to B is -20J . Find potential energy of the body in position B.

Potential energy of a body in position A is-40J. Work done by conservative force in moving the body from A to B is -20J . Find potential energy of the body in position B.

The potential energy of a particle in a conservative field is U =a/r^3-b/r^2, where a and b are positive constants and r is the distance of particle from the centre of field. For equilibrium, the value of r is

The potential energy of a particle in a conservative field is U =a/r^3 - b/r^2 where a and b are positive constants and r is the distance of particle from the centre of field. For equilibrium, the value of r is

The potential energy ‘V’ of a particle moving along the positive x-direction in a conservative force field varies as shown in the figure. The total energy is E=2. Draw the corresponding kinetic energy K vs x graph.

The potential energy ‘V’ of a particle moving along the positive x-direction in a conservative force field varies as shown in the figure. The total energy is E=2. Draw the corresponding kinetic energy K vs x graph.

Potential energy and kinetic energy of a two particle system under imaginary force field are shown by curves KE and PE. respectively in figure. This system is bound at :