A body thrown horizontally from the top of a building with a speed `20 m//s`, strikes the ground `40 m` away from the foot of tower. The height of the tower is

A body thrown horizontally from the top of a tower touches the ground at a distance of 160m from the foot of the tower.If the velocity of projection is 40m/s then the height of the tower is (g=9.8m/s^(2))

A body thrown horizontally from the top of a tower touches the ground at a distance of 160 m from the foot of the tower. If the velocity of projection is 40 m/s then the height of the towers is

A body thrown horizontally from the top of a tower touches the ground at a distance of 160 m from the foot of the tower. If the velocity of projection is 40 m/s then the height of the towers is

A body is thrown horizontally from the top of a tower of height 5m. It touches the ground at a distance of 10 m from the foot of the tower. The initial velcotiy (in m/s) of the body is (g=10ms^(-2) )

A body is thrown horizontally from the top of a tower and strikes the ground after three seconds at an angle of 45^@ with the horizontal. Find the height of the tower and the speed with which the body was projected. (Take g = 9.8 m//s^2)

A body is thrown horizontally from the top of a tower and strikes the ground after three seconds at an angle of 45^@ with the horizontal. Find the height of the tower and the speed with which the body was projected. (Take g = 9.8 m//s^2 )

A body is thrown horizontally from the top of a tower and strikes the ground after three seconds at an angle of 45^@ with the horizontal. Find the height of the tower and the speed with which the body was projected. (Take g = 9.8 m//s^2)

The angle of elevation of the top of a tower at a point on the ground, 50 m away from the foot of the tower, is 60°. Find the height of the tower.

A body is thrown horizontally from the top of a tower of height 5 m . It touches the ground at a distance of 10 m from the foot of the tower. Find the initial velocity of the body.