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1/(tan3A+tanA)-1/(cot3A+cotA)=cot4A...

`1/(tan3A+tanA)-1/(cot3A+cotA)=cot4A`

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Prove the following : 1/(tan3A-tanA)-1/(cot3A-cotA) = cot2A

1/(tan3A-tan A)-1/(cot 3A-cot A)=

Show that: (1)/(tan3A+tan A)-(1)/(cot3A+cot A)=cot4A

Show that: (1)/(tan3A-tan A)-(1)/(cot3A-cot A)=cot2A

Prove that (1)/(tan3A-tan a)-(1)/(cot3A-cot A)=cot2A

Show that : 1/(tan 3A-tanA) - 1/(cot 3A - cot A) = cot 2A

Prove the following: (frac(1)(tan3A-tanA))-(frac(1)(cot3A-cotA))=cot2A

(1)/(tan 3 A - tan A)- (1)/(cot 3 A - cot A)=

(1)/(tan 3 A - tan A)- (1)/(cot 3 A - cot A)= .............. A) tan A B) tan 2A C) cot A D) cot 2A

Prove that (1)/(tan 3A - tan A) - (1)/(cot 3A - cot A) = cot 2A .