Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :

Options

A. `{:(1,2,3,4),(iv,I,ii,iii):}`
B. `{:(1,2,3,4),(I,ii,iii,iv):}`
C. `{:(1,2,3,4),(iv,v,ii,i):}`
D. `{:(1,2,3,4),(iii,v,I,ii):}`

Answer

C

Explanation

Key Concept Spin magnetic moment can be calculated as
`mu=sqrt(n(n+2))BM`
where, `mu`=magnetic moment
BM=Bohr Magneton (unit of `mu`)
n=number of upaired electrons in d-orbital.
The electronic configuration of `CO^(3+)` is `[Ar]3d^(6)`.
Here, n=4
`mu=sqrt(4(4+2))+sqrt(24)BM`
The electronic configuration of `Cr^(3+) " is" [Ar]3d^(3)`
Here, n=3
`mu=sqrt(3(3+2))=sqrt(15)BM`
The electronic configuration of `Fe^(3+) " is " [Ar]3d^(5)`.
Here, n=5
`mu=sqrt(5(5+2))=sqrt(35)BM`
The electronic configuration of `Ni^(2+) " is" [Ar]3d^(8)`.
Here, n=2
`mu=sqrt(2(2+2))=sqrt(8)BM`
So, the correct option is ( c)`.