A boy is moving with constant velocity `12 m//s`. When he is `32 m` behind a cyclist, the cyclist starts from rest and moves under constant acceleration `2 m//s^(2)`. After how much time the boy meets the cyclist? Explain reason for two answers.

A cyclist starts from rest and moves with a constant acceleration of 1 m//s^(2) . A boy who is 48 m behind the cyclist starts moving with a constant velocity of 10 m//s . After how much time the boy meets the cyclist?

A cyclist starts from rest and moves with a constant acceleration of 1 m//s^(2) . A boy who is 48 m behind the cyclist starts moving with a constant velocity of 10 m//s . After how much time the boy meets the cyclist?

Car A starts from a point O and moves with constant velocity 9 m//s . After 2 s , another car B begins its journey from O and follows car A . If car B starts from rest and moves under constant acceleration 4 m//s^(2) , after how much time and at what distance from O the cars meet?

A boy is moving with constant velocity v_(0) on a straight road. When he is at a distance d behind the bus, the bus starts from rest and moves with a constant acceleration alpha . Find the minimum value of v_(0) so that the boy catches the bus.

Starting from rest and under constant acceleration an object covers 400 m. (i) How far does the object move in half the time ?

When two particeles A and B are at point O, A is moving with a constant velocity 50 m/s , whle B is not moving. But B possesses a constant acceleration of 10 m/ s^(2) . After how much time they will be at a distance of 125 m ?