Given : Dipole moment of `HCl=1.03` D
Bond length of `HI=0.38D`
Bond length `=161`pm
The ratio of partial positive charge on H-aotm in HCl to that in HI will be

Dipole moment of HCl = 1.03 D, Hi = 0.38D. Bond length of HCI = 1.3 Å and HI = 1.6 Å .The ratio of fraction of electric charge delta , existing on each atom in HCI and HI is

Dipole moment of HCl = 1.03 D, HI-0.38 D. Bond length of HCI-1.3 A^(@) and HI= 1.6A^(@) The ratio of fraction of electric charge, delta, existing on each atom in HCI and HI is

The observed dipole moment of HCl is 1.03D . If the bond length of HCL is 1.3Å , then the percent ionic character of H-Cl bond is

The observed dipole moment of HCl is 1.03D . If the bond length of HCL is 1.3Å , then the percent ionic character of H-Cl bond is

The observed dipole moment of HCl is 1.03D . If the bond length of HCL is 1.275Å , then the percent ionic character of H-Cl bond is

Dipole moment of HCl is 1.03D. Bond length is 1.27A^@ . Calculate the percentage ionic character of the HCl bond.

The experimental value of the dipole moment of HCl is 1.03D. The length of the H-CI bond is 1.275 A. The percentage of ionic character in HCl is:

The observed dipole moment of HCl is 1.03 D. If the H-Cl bond length is 1.275 Å, calculate the per cent ionic character in HCI.