The voltage over a cycle varies as
`V=V_(0)sin omega t` for `0 le t le (pi)/(omega)`
`=-V_(0)sin omega t` for `(pi)/(omega)le t le (2pi)/(omega)`
The average value of the voltage one cycle is

The value of an ac voltage at time 0letle(pi)/omega is given by V=V_0sinomegat and at time pi/omegaletle(2pi)/omega is given by V=-V_0sinomegat . The average value of V for a complete cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

In a given AC circuit through a specific branch the current varies as a function of time given as i=i_(0)sin^(2)omegat " " 0 le omega t lt pi and i=i_(0) sin omega t " " pi le omegat lt 2 pi Calculate the average current per cycle of this AC.

The average value of current i=I_(m) sin omega t from t=(pi)/(2 omega ) to t=(3 pi)/(2 omega) si how many times of (I_m) ?