In an experiment , the following observations were recorded:
`L = 2.820 m , M = 3.00 kg , l = 0.087 cm , diameter , D = 0.041 cm`. Taking ` g = 9.81 m s^(-2)` and using the formula , `Y = ( 4MgL)/( pi D^(2) l)` , find the maximum permissible error in `Y`.

In an experiment the following observastions are recorded. L = 2.890 m, M = 3.00 kg : a = 0.087 cm , d = 0.041 cm, g = 9.8 1 ms^(-2) , using the formula y=(4MgL)/(pi d^(2)a)

In an experiment for determining the value of acceleration due to gravity (g) using a simpe pendulum , the following observations were recorded: Length of the string (l) = 98.0 cm Diameter of the bob (d) = 2.56 cm Time for 10 oscillations (T) = 20.0 s Calculate the value of g with maximum permissible absolute error and the percentage relative error.

In an experiment for determining the value of acceleration due to gravity (g) using a simpe pendulum , the following observations were recorded: Length of the string (l) = 98.0 cm Diameter of the bob (d) = 2.56 cm Time for 10 oscillations (T) = 20.0 s Calculate the value of g with maximum permissible absolute error and the percentage relative error.

In an experiment for measurement of young's modulus, following readings are taken. Load = 3.00 kg, length = 2.820 m, diameter = 0.041 cm and extension = 0.87. We shell determine the percentage error in measurement of Y.

In an experiment for measurement of young's modulus, following readings are taken. Load = 3.00 kg, length = 2.820 m, diameter = 0.041 cm and extension = 0.87. We shell determine the percentage error in measurement of Y.

In an experiment for measurement of young's modulus, following readings are taken. Load = 3.00 kg, length = 2.820 m, diameter = 0.041 cm and extension = 0.87. We shell determine the percentage error in measurement of Y.

In resonance tube experiment , the velocity of sound is given by v = 2 f_(0) ( l_(2) - l_(1)) . We found l_(1)=25.0 cm and l_(2)=75.0 cm . If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take f_(0) = 325 Hz )

In resonance tube experiment , the velocity of sound is given by v = 2 f_(0) ( l_(2) - l_(1)) . We found l_(1)=25.0 cm and l_(2)=75.0 cm . If there is no error in frequency, what will be the maximum permissible errror in the speed of sound ? (Take f_(0) = 325 Hz )