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[(sin A+cos A)/(sin A-cos A)+(sin A-cos ...

[(sin A+cos A)/(sin A-cos A)+(sin A-cos A)/(sin A+cos A)=(2)/(sin^(2)A-cos^(2)A)=(2)/(2sin^(2)A-1)=(2)/(1-2cos^(2)A)],[" ast train takes "1" hour less than a slow train for a inurney "]

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(sin A+cos A)/(sin A-cos A)+(sin A-cos A)/(sin A+cos A)=(2)/(sin^(2)A-cos^(2)A) {Prove It}

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