[" Q "16" The equation of the line parallel to "5x+12y+1=0" and "5x+12y+7=0" and and lying midway "],[" between them is "]

The equation of the line which is parallel to 5x+12y+1=0 and 5x+12y+7=0 and lying midway between them is ( i )5x+12y+13=0(ii)5x+12y-4=0 (iii) 5x+12y+4=0(iv)5x+12y-6=0

Find the equation of two lines parallel to 5x -12y + 26 = 0 at a distance of 4 units from it.

The line which is parallel to 5x+12y+13=0 and 10x+24y+25=0 distance of and mid way between them is at a units (approx.) from origin.

The distance between the parallel lines 5x+2y+7=0 and 5x+2y+4=0 is

The distance between the parallel lines 5x-12y-14=0 and 5x-12y+12=0 is equal to

Find the distance between the parallel lines 5x+12y-20=0 and 5x+12y+6=0 .

Find the distance between the parallel lines 5x+12y-20=0 and 5x+12y+6=0 .

The distance between two parallel lines 5x-12y+2=0 and 5x-12y-3=0 is given by

The distance between two parallel lines 5x-12 y +2=0 and 5x-12 y-3=0 is given by