If in a triangle ABC ,b +c=4a then `cot(B/2)cot(C/2)` is equal to

If ina triangle ABC, b+c=3a, then cot(B/2)cot (C/2) is equal to

In a triangle ABc , if r^2cot(A/2) cot(B/2) cot(C/2)=

In a triangle ABC , if 3a = b + c , then cot B/2 cot C/2 =

With usual notations prove that in a triangle ABC, cot(A/2)+cot(B/2)+cot(C/2)=s^2/Delta

In a triangle ABC,if a cot A+b cot B+c cot C=

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC if b+c=3a then find the value of cot(B/2)cot(C/2)

In a triangle ABC if cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a and cot(C/2)cot(A/2)=b then 1/(s-a)+1/(s-b)+1/(s-c)=