Home
Class 12
CHEMISTRY
The statement "If 0.003 moles of a gas a...

The statement "If 0.003 moles of a gas are dissolved in 900 g of water under a pressure of 1 atmosphere , 0.006 moles will be dissolved under a pressure of 2 atmosphere " illustrates

A

Dalton's Law of Partial Pressures

B

Graham's law

C

Raoult's law

D

Henry's law

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • SOLUTION

    ERRORLESS |Exercise ORDINARY THINKING OBJECTIVE QUESTIONS (Methods of expressing concentration of solution )|151 Videos
  • SOLUTION

    ERRORLESS |Exercise ORDINARY THINKING OBJECTIVE QUESTIONS (Colligative properties)|12 Videos
  • SOLID STATE

    ERRORLESS |Exercise JEE section (Numeric )|1 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS |Exercise JEE Section (Matrix Match type questions)|3 Videos

Similar Questions

Explore conceptually related problems

Heating of water under atmospheric pressure is an:

0.1 gram mole of urea dissolved in 100 g of water. The molality of the solution is

6g .of Urea is dissolved in 90g .of water.The mole fraction of solute is

1 kg of water under a nitrogen pressure of 1 atmosphere dissolves 0.02 gm of nitrogenat 293 k. Calculate Henry' s law constant :

Carbon dioxide dissolve under pressure in water to give:

What happens if water vapour at a pressure of 0.003 atmosphere is cooled to 0^(@)C ?

A sample of gas occupies 10 litre under a pressure of 1 atmosphere. What will be its volume if the pressure is increased to 2 atmosphere? Assume that the temperature of the gas sample does not change

At 300 K, 40 mL of O_(3)(g) dissolves in 100g of water at 1.0atm . What mass of ozone dissolved in 400g of water at a pressure of 4.0atm at 300 K ?