Molecular weight of urea is 60. A solution of urea containing 6 g urea in one litre is

Options

A. 1 molar
B. 1.5 molar
C. 0.1 molar
D. 0.01 molar

Explanation

To solve the problem, we need to determine the molarity of the urea solution. Here are the steps to find the solution:

### Step-by-Step Solution:

1. **Identify the given data**:
- Molecular weight of urea (NH₂CO) = 60 g/mol
- Mass of urea in the solution = 6 g
- Volume of the solution = 1 L

2. **Calculate the number of moles of urea**:
- Use the formula for moles:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
- Substitute the values:
\[ \text{Number of moles} = \frac{6 \text{ g}}{60 \text{ g/mol}} = 0.1 \text{ moles} \]

3. **Calculate the molarity of the solution**:
- Molarity (M) is defined as the number of moles of solute per liter of solution:
\[ \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume of solution (L)}} \]
- Substitute the values:
\[ \text{Molarity} = \frac{0.1 \text{ moles}}{1 \text{ L}} = 0.1 \text{ M} \]

4. **Conclusion**:
- The molarity of the urea solution is 0.1 M.

### Final Answer:
The solution of urea containing 6 g of urea in one liter is 0.1 M.

---