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When 6 gm urea dissolve in 180 gm H(2)O....

When `6` gm urea dissolve in `180` gm `H_(2)O`. The mole fraction of urea is [Mol. Wt. of urea = `60`]

A

`(10)/(10.1)`

B

`(10.1)/(10)`

C

`(10.1)/(0.1)`

D

`(0.1)/(10.1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Mole fraction `X=(n)/(n + N)=((6)/(60))/((6)/(60)+(180)/(18))=(0.1)/(10.1)`.
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