20 ml of 10 N HCl are mixed with 10 ml of 36 N `H_(2)SO_(4)` and the mixture is made one litre. Normality of the mixture will be

Options

A. 0.56 N
B. 0.50 N
C. 0.40 N
D. 0.35 N

Explanation

To find the normality of the mixture when 20 ml of 10 N HCl is mixed with 10 ml of 36 N H₂SO₄ and the total volume is made up to 1 liter, we can follow these steps:

### Step 1: Identify the normalities and volumes of the solutions
- Normality of HCl (N₁) = 10 N
- Volume of HCl (V₁) = 20 ml
- Normality of H₂SO₄ (N₂) = 36 N
- Volume of H₂SO₄ (V₂) = 10 ml

### Step 2: Calculate the equivalent contributions of each solution
The total equivalents contributed by each solution can be calculated using the formula:
\[ \text{Equivalents} = \text{Normality} \times \text{Volume (in liters)} \]

For HCl:
\[ \text{Equivalents from HCl} = N₁ \times \frac{V₁}{1000} = 10 \times \frac{20}{1000} = 0.2 \text{ equivalents} \]

For H₂SO₄:
\[ \text{Equivalents from H₂SO₄} = N₂ \times \frac{V₂}{1000} = 36 \times \frac{10}{1000} = 0.36 \text{ equivalents} \]

### Step 3: Calculate the total equivalents in the mixture
Now, we add the equivalents from both solutions:
\[ \text{Total equivalents} = 0.2 + 0.36 = 0.56 \text{ equivalents} \]

### Step 4: Calculate the total volume in liters
The total volume of the mixture is made up to 1 liter.

### Step 5: Calculate the normality of the mixture
Normality of the mixture (N) can be calculated using the formula:
\[ N = \frac{\text{Total equivalents}}{\text{Total volume (in liters)}} \]
\[ N = \frac{0.56}{1} = 0.56 \text{ N} \]

### Final Answer
The normality of the mixture is **0.56 N**.

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