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6.02xx10^(23) molecules of urea are pres...

`6.02xx10^(23)` molecules of urea are present in `100 ml` of its solution. The concentration of urea solution is -

A

0.02 M

B

0.01 M

C

0.001 M

D

0.1 M

Text Solution

Verified by Experts

The correct Answer is:
B
Mole of urea `= (6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` moles
Conc. Of solution (in molarity) `=(10^(-3))/(100)xx1000 =0.01 M`.
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