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36g of glucose (molar mass = 180 g//mol)...

36g of glucose (molar mass = `180 g//mol)` is present in 500g of water, the molarity of the solution is

A

`0.2`

B

`0.4`

C

`0.8`

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
B
Molarity `=(omega xx1000)/(M xx V)`
Where V = volume of water = 500 ml
`omega` = mass of glucose = 36 g
M = mol. Mass of glucose = 180 g
Molarity `=(36xx1000)/(180xx500)=0.4M`
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