How much K(2)Cr(2)O(7) (M.W. = 294.19) i...

How much `K_(2)Cr_(2)O_(7) (M.W. = 294.19)` is required to prepare one litre of `0.1N` solution?

2.9424 g

0.4904 g

1.4712 g

0.2452 g

Text Solution

Verified by Experts

The correct Answer is:

`W=(N xx eq.wt. xx V(ml))/(1000)=(0.05xx49.04xx100)/(1000)=0.2452`.

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