Home
Class 12
CHEMISTRY
When W(B) gm solute ( molecular mass M(B...

When `W_(B)` gm solute ( molecular mass `M_(B)`) dissolves in `W_(A)` gm solvent. The molality m of the solution is

A

`(W_(B))/(W_(A))xx(M_(B))/(1000)`

B

`(W_(B))/(M_(B))xx(1000)/(W_(A))`

C

`(W_(A))/(W_(B))xx(1000)/(M_(B))`

D

`(W_(A)xxM_(B))/(W_(B)xx1000)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOLUTION

    ERRORLESS |Exercise ORDINARY THINKING OBJECTIVE QUESTIONS (Colligative properties)|12 Videos

  • SOLUTION

    ERRORLESS |Exercise ORDINARY THINKING OBJECTIVE QUESTIONS (Lowering of vapour pressure )|62 Videos

  • SOLUTION

    ERRORLESS |Exercise JEE SECTION (JEE (Advanced)2018) (Numeric answer type questions)|3 Videos

  • SOLID STATE

    ERRORLESS |Exercise JEE section (Numeric )|1 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS |Exercise JEE Section (Matrix Match type questions)|3 Videos

Similar Questions

Explore conceptually related problems

450 mg of glucose is dissolved in 100 g of solvent. What is the molality of the solution ?

When 7.1 gm Na_(2)SO_(4) ( molecular mass 142 ) dissolves in 100 ml H_(2)O ,the molarity of the solution is

The density of 2.0 M solution of a solute is 1.2 g mL^(-1) . If the molecular mass of the solute is 100 g mol^(-1) , then the molality of the solution is

Molality : It is defined as the moles of the solute pressent in 1 kg of the solvent . It is denoted by m. Molality(m) =("Number of moles of solute")/("Number of kilograms of the solvent") let w_(A) grams of the solute of molecular mass m_(A) be present in w_(B) grams of the solvent, then: Molality(m) = (w_(A))/(m_(A)xxw_(B))xx1000 Relation between mole fraction and molality: X_(A)=(n)/(N+n) "and" X_(B)=(N)/(N+n) (X_(A))/(X_(B))=(n)/(N)=("Moles of solute")/("Moles of solvent")=(w_(A)xxm_(B))/(w_(B)xxm_(A)) (X_(A)xx1000)/(X_(B)xxm_(B))=(w_(A)xx1000)/(w_(B)xxm_(A))= m or (X_(A)xx1000)/((1-X_(A))m_(B))=m If the mole fraction of a solute is changed from (1)/(4) "to" (1)/(2) in the 800 g of solvent then the ratio tof molality will be:

Molality : It is defined as the moles of the solute pressent in 1 kg of the solvent . It is denoted by m. Molality(m) =("Number of moles of solute")/("Number of kilograms of the solvent") let w_(A) grams of the solute of molecular mass m_(A) be present in w_(B) grams of the solvent, then: Molality(m) = (w_(A))/(m_(A)xxw_(B))xx1000 Relation between mole fraction and molality: X_(A)=(n)/(N+n) "and" X_(B)=(N)/(N+n) (X_(A))/(X_(B))=(n)/(N)=("Moles of solute")/("Moles of solvent")=(w_(A)xxm_(B))/(w_(B)xxm_(A)) (X_(A)xx1000)/(X_(B)xxm_(B))=(w_(A)xx1000)/(w_(B)xxm_(A))= m or (X_(A)xx1000)/((1-X_(A))m_(B))=m The mole fraction of the solute in the 12 molal solution of CaCo_(3) is :

Molality : It is defined as the moles of the solute pressent in 1 kg of the solvent . It is denoted by m. Molality(m) =("Number of moles of solute")/("Number of kilograms of the solvent") let w_(A) grams of the solute of molecular mass m_(A) be present in w_(B) grams of the solvent, then: Molality(m) = (w_(A))/(m_(A)xxw_(B))xx1000 Relation between mole fraction and molality: X_(A)=(n)/(N+n) "and" X_(B)=(N)/(N+n) (X_(A))/(X_(B))=(n)/(N)=("Moles of solute")/("Moles of solvent")=(w_(A)xxm_(B))/(w_(B)xxm_(A)) (X_(A)xx1000)/(X_(B)xxm_(B))=(w_(A)xx1000)/(w_(B)xxm_(A))= m or (X_(A)xx1000)/((1-X_(A))m_(B))=m What is the quantity of water that should be added to 16 g methonal to make the mole fraction of methonal as 0.25?

ERRORLESS -SOLUTION -ORDINARY THINKING OBJECTIVE QUESTIONS (Methods of expressing concentration of solution )
  1. The distribution law is applied for the distribution of basic acid bet...

    Text Solution

    |

  2. Volume of water needed to mix with 10 mL 10N HNO(3) to get 0.1 N HNO(3...

    Text Solution

    |

  3. Calculate the mass of sodium carbonate required to prepare 500 ml of ...

    Text Solution

    |

  4. How much K(2)Cr(2)O(7) (M.W. = 294.19) is required to prepare one litr...

    Text Solution

    |

  5. The molarity of 0.006 mole of NaCl in 100ml solution is

    Text Solution

    |

  6. When the solute is present in trace quantities the following expressio...

    Text Solution

    |

  7. When the concentration is expressed as the number of moles of a solut...

    Text Solution

    |

  8. Which of the following should be done in order to prepare 0.40 M NaCI ...

    Text Solution

    |

  9. What will be the value of molality for an aqueous solution of 10% w/W ...

    Text Solution

    |

  10. IF 10 mL of 0.1 aqueous solution of NaCl is divided into 1000...

    Text Solution

    |

  11. When W(B) gm solute ( molecular mass M(B)) dissolves in W(A) gm solven...

    Text Solution

    |

  12. Normality (N) of a solution is equal to

    Text Solution

    |

  13. 10 grams of a solute is dissolved in 90 grams of a solvent. Its mass p...

    Text Solution

    |

  14. The concentration of an aqueous solution of 0.01 M CH(3)OH solution is...

    Text Solution

    |

  15. A solution contains 25% H(2)O, 25% C(2)H(5)OH and 50% CH(3)COOH by ma...

    Text Solution

    |

  16. Essential quantity of ammonium sulphate taken for preparation of 1 mol...

    Text Solution

    |

  17. The density ("in" g mL^(-1)) of a 3.60 M sulphuric acid solution that ...

    Text Solution

    |

  18. Assertion :- One molal aqueous solution of glucose contains 180g of gl...

    Text Solution

    |

  19. Assertion :- One molal aqueous solution of urea contains 60g of urea i...

    Text Solution

    |

  20. Assertion :- If 100 cc of 0.1N HCl is mixed with 100 cc of 0.2 N HCl, ...

    Text Solution

    |