The density `("in" g mL^(-1))` of a `3.60 M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `=98 g mol^(-1)`) by mass will be:

Options

A. `1.64`
B. `1.88`
C. `1.22`
D. `1.45`

Answer

C

Explanation

Let the density of solution be 'd'
Molarity of solution given = 3.6
i.e., 1 litre of solution contains 3.6 moles of `H_(2)SO_(4)` or 1 litre of soltuion contains `3.6xx98` gms of `H_(2)SO_(4)`
Since, the solution is 20% by mass 100 gm solution contians 29 gm `H_(2)SO_(4)`
`(100)/(d)` ml solution contains 29 gm of `H_(2)SO_(4)`
1000 ml solution contains `3.6xx98` gm of `H_(2)SO_(4)`
`therefore 3.6xx98=(29xx d)/(100)xx1000 rArr d = 1.22`