Assertion :- If 100 cc of 0.1N HCl is mixed with 100 cc of 0.2 N HCl, the normality of the final solution will be 0.30.
Reason :- Normalities of similar solutions like HCl can be added.

Options

A. If both assertion and reason are true and the reason is the correct explanation of the assertion.
B. If both assertion and reason are true but reason is not the correct explanation of the assertion.
C. If assertion is true but reason is false.
D. If asserrion is false but reason is true.

Explanation

To solve the problem, we need to analyze the assertion and reason provided in the question step by step.

### Step 1: Calculate the equivalents of HCl in each solution.

1. **For 100 cc of 0.1 N HCl:**
- Normality (N) = 0.1 N
- Volume (V) = 100 cc = 0.1 L
- Equivalents (Eq) = Normality × Volume = 0.1 N × 0.1 L = 0.01 equivalents = 10 mEq (milli-equivalents)

2. **For 100 cc of 0.2 N HCl:**
- Normality (N) = 0.2 N
- Volume (V) = 100 cc = 0.1 L
- Equivalents (Eq) = Normality × Volume = 0.2 N × 0.1 L = 0.02 equivalents = 20 mEq

### Step 2: Calculate the total equivalents after mixing.

- Total equivalents = Equivalents from 0.1 N HCl + Equivalents from 0.2 N HCl
- Total equivalents = 10 mEq + 20 mEq = 30 mEq

### Step 3: Calculate the total volume of the mixed solution.

- Total volume = Volume of 0.1 N HCl + Volume of 0.2 N HCl
- Total volume = 100 cc + 100 cc = 200 cc = 0.2 L

### Step 4: Calculate the normality of the final solution.

- Resultant Normality (N) = Total equivalents / Total volume (in liters)
- Resultant Normality = 30 mEq / 0.2 L = 150 mEq/L = 1.5 N

### Conclusion:

- The assertion states that the normality of the final solution will be 0.30, which is incorrect as we calculated it to be 1.5 N.
- The reason states that normalities of similar solutions like HCl can be added, which is true, but since the assertion is false, the overall statement is false.

### Final Answer:

Both the assertion and reason are false.

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