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The mass of a non-volatile solute of mol...

The mass of a non-volatile solute of molar mass `40g" "mol^(-1)` that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is

A

10 g

B

11.4 g

C

9.8 g

D

12.8 g

Text Solution

Verified by Experts

The correct Answer is:
A
Using Raoult's Law,
`(P_(o)-P_(s))/(P_(s))=(w)/(m)xx(M)/(W)`
If `P_(o)=100 mm`, then `P_(s)=80mm`
`(100-80)/(80)=(w)/(114)xx(114)/(40) " " therefore " " w=10 g`
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