1.00 g of a non-electrolyte solute (molar mass 250g `mol^(–1)`) was dissolved in 51.2 g of benzene. If the freezing point depression constant `K_(f)` of benzene is 5.12 K kg `mol^(–1)`, the freezing point of benzene will be lowered by:-

Options

A. 0.5 K
B. 0.2 K
C. 0.4 K
D. 0.3 K

Answer

C

Explanation

`Delta T_(f)=(K_(f)xx W_(B)xx1000)/(M_(B)xx W_(A))`
`Delta T_(f)=(5.12xx1.0xx1000)/(250xx51.2)`
`Delta T_(f)=0.4 K`