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0.440 g of a substance dissolved in...

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by `0.567 ^(@)C ` . The molecular mass of the substance is _____`(K_(f) = 5.12 K kg mol ^(-1))`

A

`178.9`

B

`177.8`

C

`176.7`

D

`175.6`

Text Solution

Verified by Experts

The correct Answer is:
A
`m=(K_(f)xx w xx1000)/(Delta T_(f)xx W)=(5.12xx0.440xx1000)/(0.567xx22.2)=178.9`
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