When 0.01 mole of sugar is dissolved in 100 g of a solvent the despersion is frezzing point is `0.40^(@)C` . When 0.03 mole of glucose is dissolved in 50 g of the same solvent , the depression in freezing point will be __________.

Options

A. `0.60^(@)`
B. `0.80^(@)`
C. `1.60^(@)`
D. `2.40^(@)`

Answer

D

Explanation

`Delta T_(f)=mk_(f)`
`0.40=(0.01xx1000)/(100)xx k_(f)rArr k_(f)=4`
again `Delta T_(f)=mk_(f)`
`=(0.03xx1000)/(50)xx4=2.4`