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K(f) of 1,4-"dioxane is" 4.9mol^(-1) for...

`K_(f) of 1,4-"dioxane is" 4.9mol^(-1)` for `1000g`.The depression in freezing point for a`0.001m` solution in dioxane is

A

`0.0049`

B

`4.9+0.001`

C

`4.9`

D

`0.49`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T=K_(f)xx` Molality `= 4.9xx0.001=0.0049 K`
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