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The van't Hoff factor for 0.1 M Ba(NO(3)...

The van't Hoff factor for `0.1 M Ba(NO_(3))_(2)` solution is `2.74` . The degree of dissociation is :

A

`91.7%`

B

`87%`

C

`100%`

D

`74%`

Text Solution

Verified by Experts

The correct Answer is:
B

Explanation : `Ba(NO_(3))_(2)to Ba^(2+)+2NO_(3)^(-)rArr n=3 rArr alpha =(i-1)/(n-1)=(2.74-1)/(3-1)=(1.74)/(2)=0.87 rArr alpha = 87%`.
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