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The molal freezing point constant of wat...

The molal freezing point constant of water is `1.86 K m^(-1)`. If `342 g` of cane sugar `(C_(12)H_(22)O_(11))` is dissolved in `1000 g` of water, the solution will freeze at

A

`-1.86^(@)C`

B

`1.86^(@)C`

C

`-3.92^(@)C`

D

`2.43^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T_(f)=1.86xx((342)/(342))=1.86^(@)C, therefore T_(f)=-1.86^(@)C`.
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