The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:

Options

A. `0.16`
B. `0.05`
C. `0.1`
D. `0.2`

Answer

A

Explanation

`Delta T_(b)=i.K_(b).m`
`{:(CuCl_(2),rarr,Cu^(2+),+,2Cl^(-)),(1,,0,,0),((1-alpha),,alpha,,2alpha):}`
`i=1+2alpha`
Assuming 100% ionization
So, i=3
`Delta T_(b)=3xx0.52xx0.1=0.156~~0.16`