Home
Class 12
CHEMISTRY
The freezing point (in .^(@)C) of a solu...

The freezing point (in `.^(@)C)` of a solution containing `0.1 g` of `K_(3)[Fe(CN)_(6)]` (Mol.wt. 329) in 100 g of water `(K_(f) = 1.86 K kg mol^(-1))` is

A

`-2.3xx10^(-2)`

B

`-5.7xx10^(-2)`

C

`-5.7xx10^(-3)`

D

`-1.2xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T_(f)=ixx K_(f)xx m`
`=4xx1.86xx(0.1)/(329xx0.1)=2.3xx10^(-2)`
`rArr T_(f)=0-2.3xx10^(-2)=-2.3xx10^(-2) .^(@)C`.
`rArr V = 6 mL`.
Promotional Banner

Topper's Solved these Questions

  • SOLUTION

    ERRORLESS |Exercise JEE SECTION (More than one choice correct answer)|13 Videos

  • SOLUTION

    ERRORLESS |Exercise JEE SECTION (Reasoning type questions)|2 Videos

  • SOLUTION

    ERRORLESS |Exercise Critical Thinking (Objective Questions)|28 Videos

  • SOLID STATE

    ERRORLESS |Exercise JEE section (Numeric )|1 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS |Exercise JEE Section (Matrix Match type questions)|3 Videos

Similar Questions

Explore conceptually related problems

The freezing point (in .^(@)C) of a solution containing 0.1g of K_(3)[Fe(CN)_(6)] (Mol. wt. 329 ) in 100 g of water (K_(f) = 1.86 K kg mol^(-1)) is :

Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solution molecules ae added to get homogeneous solution. These are called colligative properties. Application colligative properties are very useful in day-to-day life. One of its example is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9 Given: Freezing point depression of water (K_(f)^("water"))=1.86K kg "mol"^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol")=2.0K kg "mol"^(-1) Boiling point elevation constant of water (K_(b)^("water")=0.52K kg "mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol")=1.2K kg "mol"^(-1) Standard freezing point of water =273K Standard freezing point of ethanol =155.7K Standard boiling point of water =373K Stadndard boiling point of ethanol =351.5K Vapour pressure of pure water =32.8mm Hg Vapour pressure of pure ethanol =40mm Hg Molecular weight of water =18 g "mol"^(-1) Molecular weight of ethanol =46g "mol"^(-1) In aswering the following questions, consider the solution to be ideal dilute solutions and solutes to be non volatile and non-dissociative. The freezing point (in .^(@)C ) of a solution containing 0.1g of K_(3)[Fe(CN)_(6)] (Mol. Wt. 329 ) in 100g of water (K_(f)=1.86K kg "mol"^(-1) is :

The freezing point ( "in"^(@)"C" ) of a solution containing 0.1 g of K_(3)[Fe(CN)_(6)] ( Mol. Wt. 329) in 100g of water ( K_(f)"=1.86 k kg mol"^(-1)) is

The freezing point (in .^@C ) of solution containing 0.1 g of K_(3)[Fe(CN)_(6)] (molecular weight 329) in 100 g of water (K_(f) = 1.86 K kg mol^(-1)) is

The freezing point (.^(@)C) of a solution containing 0.1 g of K_(3)[Fe(CN)_(6)] (molecular weight 329) on 100 g of water (K_(f)=1.86 K kg mol^(-1))

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

What will be the freezing point ("in"^(@)C) of solution obtained by dissolving 0.1 g potassium ferricyanide (mol wt = 329) in 100 g water. If K_(f) for water is 1.86 K kg mol^(-1)

ERRORLESS -SOLUTION -JEE SECTION (Only one choice correct answer)
  1. The van't Hoff factor for 0.1 M Ba(NO(3))(2) solution is 2.74 . The de...

    Text Solution

    |

  2. The normality of 0.3 M phosphorous acid (H(3) PO(3)) is

    Text Solution

    |

  3. A 0.6% urea solution would be isotonic with :

    Text Solution

    |

  4. The molal freezing point constant of water is 1.86 K m^(-1). If 342 g...

    Text Solution

    |

  5. Which of the following solutions in water will have the lowest vapour ...

    Text Solution

    |

  6. During depression of freezing point in a solution, the following are i...

    Text Solution

    |

  7. The elevation in boiling point of a solution of 13.44g of CuCl(2)(mole...

    Text Solution

    |

  8. 75.2 g of C(6)H(5)OH (phenol) is dissolved in a solvent of K(f) = 14. ...

    Text Solution

    |

  9. When 20 g of naphthoic acid (C(11)H(8)O(2)) is dissolved in 50 g of be...

    Text Solution

    |

  10. The Henry's law constant fo the solubility of N(2) gas in water at 29...

    Text Solution

    |

  11. Dissolving 120g of urea (mol wt = 60) in 1000g of water gave a solutio...

    Text Solution

    |

  12. The freezing point (in .^(@)C) of a solution containing 0.1 g of K(3)[...

    Text Solution

    |

  13. For a dilute solution containing 2.5g of a non-volatile non-electrolyt...

    Text Solution

    |

  14. The molarity of a solution obtained by mixing 800 mL of 0.5 M HCl with...

    Text Solution

    |

  15. Consider separate solutions of 0.500 M C(2)H(5)OH(aq),0.100 M Mg(3)(PO...

    Text Solution

    |

  16. The vapour pressure of acetone at 20^(@)C is 185 torr. When 1.2 g of n...

    Text Solution

    |

  17. 18g of glucose (C(6)H(12)O(6))is added to 178.2 g of water. The vapour...

    Text Solution

    |

  18. The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of ace...

    Text Solution

    |

  19. Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethan...

    Text Solution

    |

  20. For 1 molal aqueous solution of the following compounds, which one wil...

    Text Solution

    |