Statement 1 : Lowering of vapour pressure is directly proportional to the number of species present in the solution.
Statement 2 : The vapour pressure of 0.1M sugar solution is more than 0.1 M KCl solution.

Options

A. Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 2
B. Statement 1 is true, statement 2 is true , statement 2 is not a correct explanation for statement 2
C. Statement 1 is true, statement 2 is false
D. Statement 1 is false, statement 2 is true

Explanation

To analyze the given statements, we will break down each statement and evaluate their validity based on the principles of colligative properties.

### Step 1: Evaluate Statement 1
**Statement 1:** Lowering of vapor pressure is directly proportional to the number of species present in the solution.

**Explanation:**
- Colligative properties, including vapor pressure lowering, depend on the number of solute particles in a solution rather than their identity.
- When a non-volatile solute is added to a solvent, the vapor pressure of the solvent decreases. The extent of this decrease is directly related to the number of solute particles in the solution.
- Therefore, this statement is **true**.

### Step 2: Evaluate Statement 2
**Statement 2:** The vapor pressure of 0.1 M sugar solution is more than 0.1 M KCl solution.

**Explanation:**
- Sugar (C₁₂H₂₁O₁₁) is a non-electrolyte and does not dissociate in solution. Therefore, a 0.1 M sugar solution has 0.1 moles of solute particles per liter.
- KCl, on the other hand, is an electrolyte and dissociates into two ions (K⁺ and Cl⁻) when dissolved in water. Thus, a 0.1 M KCl solution produces 0.2 moles of solute particles per liter (0.1 M KCl → 0.1 M K⁺ + 0.1 M Cl⁻).
- Since the vapor pressure lowering is greater for solutions with more solute particles, the vapor pressure of the KCl solution will be lower than that of the sugar solution.
- Therefore, this statement is **true**.

### Conclusion:
Both statements are true.