The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(5)Cl]Cl_(2)`, as silver chloride is close to:

Answer

6

Explanation

m moles of `[Cr(H_(2)O)_(5)Cl]Cl_(2)=0.01xx30=0.3`
`rArr` m mole of `Cl^(-)=0.3xx2=0.6`
`rArr` m mole of `Ag^(+)` = m moles of `Cl^(-)`
`rArr 0.1xx V=0.6`
`rArr V=6 mL`.