In diborane, the H-B-H bond angle is `120^(@)`. The hybridization of borons is likely to be

Options

A. `sp`
B. `sp^(2)`
C. `sp^(3)`
D. `dsp^(2)`

Answer

To determine the hybridization of boron in diborane (B2H6) based on the given bond angle of H-B-H being 120 degrees, we can follow these steps:

### Step 1: Understand the Structure of Diborane
Diborane (B2H6) consists of two boron atoms and six hydrogen atoms. The arrangement of these atoms is crucial for determining hybridization.

**Hint:** Recall the molecular formula and the number of hydrogen atoms bonded to boron.

### Step 2: Analyze the Bond Angle
The bond angle of H-B-H is given as 120 degrees. This bond angle suggests a trigonal planar arrangement around each boron atom.

**Hint:** Remember that a bond angle of 120 degrees is characteristic of sp2 hybridization.

### Step 3: Determine the Hybridization
Since the bond angle is 120 degrees, we can conclude that the hybridization of the boron atoms in diborane is sp2. In sp2 hybridization, one s orbital and two p orbitals mix to form three sp2 hybrid orbitals that are arranged in a trigonal planar geometry.

**Hint:** Consider how many orbitals are involved in forming the bonds and the resulting geometry.

### Step 4: Conclusion
Therefore, the hybridization of boron in diborane (B2H6) is sp2.

**Final Answer:** The hybridization of borons in diborane is sp2.