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The paramagnetic behaviour of B2 is due ...

The paramagnetic behaviour of `B_2` is due to the presence of

A

2 unpaired electrons in `pi_(n) MO`

B

`2 unpaired electrons in `pi^(**) MO`

C

2 unpaired electrons in `sigma^(**)MO`

D

2 unpaired electrons in `sigma_(b)MO`

Text Solution

Verified by Experts

The correct Answer is:
A

`B_(2)`(electrons=10)
`sigma(1s)^(2),sigma^(**)(1s)^(2),sigma(2s)^(2),sigma^(**)(2s)^(2),pi(2p_(x))^(1),pi(2p_(y))^(1)`
Thus paramagnetic behaviour of `B_(2)` is due to the presence of two unpaired electrons in `pi`-bonding molecular orbital.
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