In CsCl structure, the coordination number of `Cs^(+)` is

Options

A. Equal to that of `Cl^(-)`, that is 6
B. Equal to that of `Cl^(-)` that is 8
C. Not equal to that of `Cl^(-)`, that is 6
D. Not equal to that of `Cl^(-)`, that is 8

Explanation

To determine the coordination number of \( Cs^+ \) in the CsCl structure, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure**: The CsCl crystal structure is characterized as a body-centered cubic (BCC) lattice. In this structure, the \( Cs^+ \) ions are located at the body center of the cube, while the \( Cl^- \) ions are located at the corners of the cube.

2. **Identify the Position of Ions**: In the BCC structure, the \( Cs^+ \) ion occupies the center of the cube, and the \( Cl^- \) ions occupy the eight corners of the cube.

3. **Count the Nearest Neighbors**: The coordination number is defined as the number of nearest neighbor ions surrounding a particular ion. For the \( Cs^+ \) ion at the center, it is surrounded by the \( Cl^- \) ions located at the corners of the cube.

4. **Determine the Coordination Number**: Since there are 8 corners in the cube and each corner \( Cl^- \) ion is a nearest neighbor to the \( Cs^+ \) ion, the coordination number of \( Cs^+ \) is 8.

5. **Conclusion**: Therefore, the coordination number of \( Cs^+ \) in the CsCl structure is 8.

### Final Answer:
The coordination number of \( Cs^+ \) in the CsCl structure is **8**.

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