Stable nuclides are those whose n/p ratio is

Options

A. `n//p = 1`
B. `n//p=2`
C. `n//p gt 1`
D. `n//p lt 1`

Explanation

To determine the n/p (neutron to proton) ratio for stable nuclides, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Role of Neutrons and Protons**:
- Protons are positively charged and repel each other due to electrostatic forces. This repulsion can lead to instability in the nucleus if not balanced by other forces.

2. **Importance of Neutrons**:
- Neutrons, which have no charge, help to mitigate the repulsive forces between protons. The presence of neutrons adds to the nuclear force that holds the nucleus together without contributing to repulsion.

3. **Determining the Ratio**:
- For a nucleus to be stable, the number of neutrons (N) should be greater than the number of protons (P). This is because more neutrons can help to reduce the repulsion among protons.
- Therefore, we can express this relationship as \( N > P \).

4. **Mathematical Representation**:
- From the above relationship, we can derive that the neutron to proton ratio (n/p) must be greater than 1. This can be expressed as:
\[ \frac{N}{P} > 1 \]

5. **Optimal Ratio for Stability**:
- It is noted that the most stable nuclei have an n/p ratio around 1.4. This means that for optimal stability, the number of neutrons should be approximately 1.4 times the number of protons.

6. **Conclusion**:
- Thus, we conclude that stable nuclides are characterized by an n/p ratio that is greater than 1, with the most stable nuclides having an n/p ratio around 1.4.

### Final Answer:
Stable nuclides are those whose n/p ratio is greater than 1, with the most stable nuclei having an n/p ratio around 1.4.