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Uranium U92^235 on bombardment with slow...

Uranium `U_92^235` on bombardment with slow neutrons produces

A

Deutrons

B

Fusion reaction

C

Fission reaction

D

Endothermic reaction

Text Solution

Verified by Experts

The correct Answer is:
C

`._(92)U^(235) + ._(0)n^(1) rarr ._(56)Ba^(145) + ._(36)Kr^(88) + 3 ._(0)^(1)n`
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When a uranium isotope ""_(92)^(235)U is bombared with neutron, it generates ""_(36)^(89)Kr three neutrons and

When a uranium isotope U is bombarded with a neutron, it generates kr three neutrons

Knowledge Check

  • Assertion:There occurs a chain reaction when uranium is bombarded with slow neutrons. Reason:When uranium is bombarded with slow neutrons more neutrons are produced

    A
    If both assertion and reason are true and reason is the correct explanation of assertion .
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion .
    C
    If assertion is true but reason is false .
    D
    If both assertion and reason are false
  • When _92U^235 is bombarded with one neutron, fission occurs and the products are three neutrons, _36Kr^139 , and :

    A
    `_56Ba^141`
    B
    `-54Xe^139`
    C
    `_56Ba^139`
    D
    `_58I^142`
  • When _92U^235 is bombarded with one neutron, fission occurs and the products are three neutrons, _36Kr^139 , and :

    A
    `_56Ba^141`
    B
    `-54Xe^139`
    C
    `_56Ba^139`
    D
    `_58I^142`
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    Assertion (A) : When U-235 isotope is bombarded by slow neutrons , nuclear fission takes place with a release of about 200 Me V of energy . Reason (R) : The disintegration energy is fission event first appears as the kinetic energy of fragments and neutrons but eventually it is transferred to the surrounding matter appearing as heat .

    When U^235 is bombarded with one neutron, the fission occurs and the products are three neutrons, ._36 Kr^94 and.

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