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In a chemical equilibrium A + B hArr C ...

In a chemical equilibrium `A + B hArr` C + D, when one mole each of the two reactants are mixed, `0.6` mole each of the products are formed. The equilibrium constant calculated is

A

1

B

`0.36`

C

`2.25`

D

`4//9`

Text Solution

Verified by Experts

The correct Answer is:
C
`A+BhArrC+D`
initial `1" "1" "0" "0`
Remaining at equlibrium `0.4" "0.4" "0.6" "0.6`
`K=([C][D])/([A][B])=(0.6xx0.6)/(0.4xx0.4)=36/16=2.25.`
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