`Deltan,` the change in the number of moles for the reactin, `C_(12)H_(22)O_(11(s))+12O_(2(g))hArr12CO_(2(g))+11H_(2)O_((1))at 25^(@)C` is

Options

A. 0
B. 2
C. 4
D. `-1`

Explanation

To determine the change in the number of moles (Δn) for the given reaction, we need to analyze the stoichiometry of the reactants and products. The reaction is:

\[ C_{12}H_{22}O_{11(s)} + 12O_{2(g)} \rightleftharpoons 12CO_{2(g)} + 11H_{2}O_{(l)} \]

### Step 1: Identify the reactants and products
- Reactants:
- 1 mole of \( C_{12}H_{22}O_{11} \) (solid)
- 12 moles of \( O_{2} \) (gas)

- Products:
- 12 moles of \( CO_{2} \) (gas)
- 11 moles of \( H_{2}O \) (liquid)

### Step 2: Count the moles of gaseous reactants and products
- Gaseous reactants:
- \( O_{2} \): 12 moles

- Gaseous products:
- \( CO_{2} \): 12 moles

### Step 3: Calculate Δn
Δn is defined as the change in the number of moles of gas during the reaction:

\[ \Delta n = \text{(moles of gaseous products)} - \text{(moles of gaseous reactants)} \]

Substituting the values we found:

\[ \Delta n = (12 \text{ moles of } CO_{2}) - (12 \text{ moles of } O_{2}) \]

\[ \Delta n = 12 - 12 = 0 \]

### Final Answer
The change in the number of moles (Δn) for the reaction is **0**.

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