Home
Class 12
CHEMISTRY
At a given temperature the equilibrium c...

At a given temperature the equilibrium constant for the reaction of
`PCl_(5)hArrPCl_(3)+Cl_(2)` is `2.4xx10^(-3)`. At the same temperature, the equilibrium constant for the reaction
`PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)` is :

A

`2.4xx10^(-3)`

B

`-2.4xx10^(-3)`

C

`-4.2xx10^(2)`

D

`4.8xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C

Reaction is reversed. Hence
`K=(1)/((2.4xx10^(3)))=4.2xx10^(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

At a given temperature the equilibrium constant for the reaction PCl_(5) (g) Leftrightarrow PCl_(3)(g)+Cl_(2)(g) is 2.4 xx 10^(-3) . At the same temperature the equilibrium constant for the reaction PCl_(3) (g)+Cl_(2)(g) Leftrightarrow PCl_(5) (g)

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

The equilibrium constant for the following reactions are K_(1) and K_(2) , respectively , 2P(g)+3Cl_(2)(g)hArr2PCl_(3)(g) PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g) Then the equilibrium constant for the reaction 2P(g)+5Cl_(2)(g)hArr2PCl_(5)(g) is -